document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=749841>Question 749841</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much 12% acid must be added to 16 gallons of pure water to get a mixture that is 7% acid? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #456172 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=456172\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (amount of pure acid)/(amount of mixture)=(concentration of acid)\r<BR>\n" );
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document.write( "let g = gallons of the 12% acid to use.\r<BR>\n" );
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document.write( "12*g would represent amount of acid, although 100 times larger<BR>\n" );
document.write( "g+16 would be total gallons of mixture\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=12%2Ag%2F%28g%2B16%29=7 ALIGN=MIDDLE  ALT=\"12%2Ag%2F%28g%2B16%29=7\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Solve for g. </SPAN>\n" );
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