document.write( "Question 65131: Please sold this problem.
\n" ); document.write( "The sum of 2 numbers is 28 and their product is 96. Find the numbers.
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Algebra.Com's Answer #45615 by Earlsdon(6294)\"\" \"About 
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Let the two numbers be x and y.
\n" ); document.write( "1) x+y = 28 Rewrite this as: x = 28-y and substitute for x in equation 2).\r
\n" ); document.write( "\n" ); document.write( "2) \"x%2Ay+=+96\"
\n" ); document.write( "2a) \"%2828-y%29%2Ay+=+96\" Simplify this:
\n" ); document.write( "\"28y+-+y%5E2+=+96\" Now add \"y%5E2\" to both sides of the equation.
\n" ); document.write( "\"28y+=+y%5E2+%2B+96\" Subtract 28y from both sides.
\n" ); document.write( "\"y%5E2+-+28y+%2B+96+=+0\" Solve this quadratic equation by factoring.
\n" ); document.write( "\"%28y+-+4%29%28y+-+24%29+=+0\" Apply the zero product principle.
\n" ); document.write( "\"y+-+4+=+0\" and \"y+-+24+=+0\"
\n" ); document.write( "If \"y+-+4+=+0\" then \"y+=+4\"
\n" ); document.write( "If \"y+-+24+=+0\" then \"y+=+24\"
\n" ); document.write( "The two numbers are: 4 and 24.\r
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