document.write( "Question 749560: I can not seem to figure this question out...\r
\n" ); document.write( "\n" ); document.write( "log[4](x+3)-log[4](x+2) >= 3/2
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Algebra.Com's Answer #456122 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
For \"log%284%2C%28x%2B3%29%29\" and \"log%284%2C%28x%2B2%29%29\"to exist, it must be that \"x%2B3%3Ex%2B2%3E0\" <--> \"x%3E-2\"
\n" ); document.write( "(because logarithm exist only for positive numbers).
\n" ); document.write( "\"log%284%2C%28x%2B3%29%29-log%284%2C%28x%2B2%29%29%3E=3%2F2\" --> \"log%284%2C%28%28x%2B3%29%2F%28x%2B2%29%29%29%3E=3%2F2\" --> \"%28x%2B3%29%2F%28x%2B2%29%3E=4%5E%283%2F2%29\" --> \"%28x%2B3%29%2F%28x%2B2%29%3E=%282%5E2%29%5E%283%2F2%29\" --> \"%28x%2B3%29%2F%28x%2B2%29%3E=2%5E%28%282%2A3%2F2%29%29\" --> \"%28x%2B3%29%2F%28x%2B2%29%3E=2%5E3\" --> \"%28x%2B3%29%2F%28x%2B2%29%3E=8\"
\n" ); document.write( "Since \"x%2B2%3E0\", multiplying both sides times \"%28x%2B2%29\" does not require flipping the inequality sign, so
\n" ); document.write( "\"%28x%2B3%29%2F%28x%2B2%29%3E=8\" --> \"x%2B3%3E=8%2A%28x%2B2%29\" --> \"x%2B3%3E=8x%2B16\" --> \"3-16%3E=8x-x\" --> \"-13%3E=7x\" --> \"-13%2F7%3E=x\"
\n" ); document.write( "The solution is \"highlight%28-2%3Cx%3C=-13%2F7%29\"
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