document.write( "Question 749627: Find all real zeros of the function. f(x)=x^3+6x^2-4x-24 \n" ); document.write( "

Algebra.Com's Answer #456120 by Edwin McCravy(20056) $\"\"$ $\"About$

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f(x) = x³+6x²-4x-24
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document.write( "Factor x² out of the first two terms\r\n" );
document.write( "Factor -4 out of the last two terms\r\n" );
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document.write( "f(x) = x²(x+6)-4(x+6)\r\n" );
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document.write( "Factor (x+6) out of both terms:\r\n" );
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document.write( "f(x) = (x+6)(x²-4)\r\n" );
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document.write( "Factor the second parentheses as the difference of squares:\r\n" );
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document.write( "f(x) = (x+6)(x-2)(x+2)\r\n" );
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document.write( "To find the zeros set the expression = 0\r\n" );
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document.write( "       (x+6)(x-2)(x+2) = 0\r\n" );
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document.write( "Use the zero factor property:\r\n" );
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document.write( "        x+6=0; x-2=0;  x+2=0\r\n" );
document.write( "         x=-6;   x=2;    x=-2\r\n" );
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document.write( "Edwin

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