document.write( "Question 749685: need help solving this problem please.
\n" ); document.write( "A tank contains 55 gallons of a 55% solution of antifreeze. How much solution needs to be drained out and replaced with pure antifreeze to obtain a 70% solution?
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Algebra.Com's Answer #456119 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
The key here is to realize that you start with
\n" ); document.write( "55 gallons and end up with 55 gallons
\n" ); document.write( "Let \"+x+\" = gallons of solution to be drained
\n" ); document.write( "and replaced with pure antifreeze
\n" ); document.write( "\"+.55x+\" = gallons of antifreeze removed
\n" ); document.write( "\"+.55%2A55+=+30.25+\" gallons of antifreeze
\n" ); document.write( "in original mixture
\n" ); document.write( "----------------------------
\n" ); document.write( "\"+%28+30.25+-+.55x+%2B+x+%29+%2F+55+=+.7+\"
\n" ); document.write( "\"+%28+30.25+%2B+.45x+%29+%2F+55+=+.7+\"
\n" ); document.write( "\"+30.25+%2B+.45x+=+.7%2A55+\"
\n" ); document.write( "\"+30.25+%2B+.45x+=+38.5+\"
\n" ); document.write( "\"+.45x+=+8.25+\"
\n" ); document.write( "\"+x+=+18.333+\"
\n" ); document.write( "18.333 gallons of solution must be drained and
\n" ); document.write( "replaced with pure antifreeze
\n" ); document.write( "check:
\n" ); document.write( "\"+%28+30.25+%2B+.45x+%29+%2F+55+=+.7+\"
\n" ); document.write( "\"+%28+30.25+%2B+.45%2A18.333+%29+%2F+55+=+.7+\"
\n" ); document.write( "\"+38%2C5+%2F+55+=+.7+\"
\n" ); document.write( "\"+38.5+=+.7%2A55+\"
\n" ); document.write( "\"+38.5+=+38.5+\"
\n" ); document.write( "OK
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