document.write( "Question 749673: Using the facts that log2 = 0.3010 and log3 = 0.4771, find the values of the following
\n" ); document.write( "a) log6
\n" ); document.write( "b) log1.5
\n" ); document.write( "c) log1/2\r
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\n" ); document.write( "\n" ); document.write( "Can you please help me out? Thanks so much in advance
\n" ); document.write( "Also can you please show the steps it would really help me understand better:)
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Algebra.Com's Answer #456115 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
You need to follow 2 general rules
\n" ); document.write( "(1) \"+log%28%28+a%2Ab+%29%29+=+log%28a%29+%2B+log%28b%29+\"
\n" ); document.write( "(2) \"+log%28%28+a%2Fb+%29%29+=+log%28a%29+-+log%28b%29+\"
\n" ); document.write( "-----------------------------
\n" ); document.write( "(a)
\n" ); document.write( "\"+log%28+6+%29+=+log%28+2%2A3+%29+\"
\n" ); document.write( "\"+log%28%28+2%2A3+%29%29+=+log%28+2+%29+%2B+log%28+3+%29+\"
\n" ); document.write( "\"+log%28+2+%29+%2B+log%28+3+%29+=+.301+%2B+.4771+\"
\n" ); document.write( "\"+log%28+6+%29+=+.7781+\"
\n" ); document.write( "---------------------------------
\n" ); document.write( "(b)
\n" ); document.write( "\"+log%28+1.5+%29+=+log%28%28+3%2F2+%29%29+\"
\n" ); document.write( "\"+log%28%28+3%2F2+%29%29+=+log%28+3+%29+-+log%28+2+%29+\"
\n" ); document.write( "\"+log%28+3+%29+-+log%28+2+%29+=+.4771+-+.301+\"
\n" ); document.write( "\"+log%28+1.5+%29+=+.1761+\"
\n" ); document.write( "--------------------------------
\n" ); document.write( "(c)
\n" ); document.write( "\"+log%28%28+1%2F2+%29%29+=+log%28+1+%29+-+log%28+2+%29+\"
\n" ); document.write( "\"+log%281%29+-+log%28+2+%29+=+0+-+.301+\"
\n" ); document.write( "\"+log%28%28+1%2F2+%29%29+=+-.301+\"
\n" ); document.write( "----------------------------
\n" ); document.write( "Note that \"+a%5E0+=+1+\" for any value of \"+a+\",
\n" ); document.write( "so \"+log%28+a%2C+1+%29+=+0+\" for any value of \"+a+\"
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