document.write( "Question 749671: you have been asked to design a small box. the width is 1 inch more than the depth. length is 3 inches more than the depth. volume is 30 cubic inches. what are the dimensions? \n" ); document.write( "
Algebra.Com's Answer #456106 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! you have been asked to design a small box. \n" ); document.write( "the width is 1 inch more than the depth. \n" ); document.write( "Let depth be \"x\" \n" ); document.write( "Then width is \"x+1\" \n" ); document.write( "--- \n" ); document.write( "length is 3 inches more than the depth. \n" ); document.write( "And length is \"x+3\" \n" ); document.write( "---- \n" ); document.write( "volume is 30 cubic inches. \n" ); document.write( "x(x+1)(x+3) = 30 in^3 \n" ); document.write( "------ \n" ); document.write( "x(x^2+4x+3) = 30 \n" ); document.write( "x^3 + 4x^2+3x-30 = 30 \n" ); document.write( "Solution: x = 2 \n" ); document.write( "------------------------ \n" ); document.write( "what are the dimensions? \n" ); document.write( "depth = 2 in \n" ); document.write( "width = 3 in \n" ); document.write( "length = 5 in \n" ); document.write( "================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=================== \n" ); document.write( " |