document.write( "Question 749529:
\n" ); document.write( "Two trains were 332 miles apart and heading towards each other at 11 am. If the trains meet at 1 pm and one train was traveling 36 miles per hour faster than the other, then how fast was each train moving?
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Algebra.Com's Answer #456055 by checkley79(3341)\"\" \"About 
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D=RT
\n" ); document.write( "332=R*3
\n" ); document.write( "R=332/3
\n" ); document.write( "R=110.67 TOTAL SPEED OF THE 2 CARS.
\n" ); document.write( "X+X+36=110.67
\n" ); document.write( "2X=110.67-36
\n" ); document.write( "2X=74.67
\n" ); document.write( "X=74.67/2
\n" ); document.write( "X=37.335 MPH FOR THE SLOWER CAR.
\n" ); document.write( "37.335+36=73.335 MPH FOR THE FASTER CAR.
\n" ); document.write( "PROOF:
\n" ); document.write( "332=(37.335+73.335)*3
\n" ); document.write( "332=110.67*3
\n" ); document.write( "332=332
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