document.write( "Question 749529:
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document.write( "Two trains were 332 miles apart and heading towards each other at 11 am. If the trains meet at 1 pm and one train was traveling 36 miles per hour faster than the other, then how fast was each train moving? \n" );
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Algebra.Com's Answer #456055 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "332=R*3 \n" ); document.write( "R=332/3 \n" ); document.write( "R=110.67 TOTAL SPEED OF THE 2 CARS. \n" ); document.write( "X+X+36=110.67 \n" ); document.write( "2X=110.67-36 \n" ); document.write( "2X=74.67 \n" ); document.write( "X=74.67/2 \n" ); document.write( "X=37.335 MPH FOR THE SLOWER CAR. \n" ); document.write( "37.335+36=73.335 MPH FOR THE FASTER CAR. \n" ); document.write( "PROOF: \n" ); document.write( "332=(37.335+73.335)*3 \n" ); document.write( "332=110.67*3 \n" ); document.write( "332=332 \n" ); document.write( " \n" ); document.write( " |