document.write( "Question 749527: A woman's age added thrice her daughter's age amounts to 80years. Five years ago,she was nine times as old as her daughter. How old is each now? \n" ); document.write( "
| Algebra.Com's Answer #456033 by lwsshak3(11628)      You can put this solution on YOUR website! A woman's age added thrice her daughter's age amounts to 80years. Five years ago,she was nine times as old as her daughter. How old is each now? \n" ); document.write( "*** \n" ); document.write( "Now: \n" ); document.write( "let x=daughter's age \n" ); document.write( "let y=woman's age \n" ); document.write( "y+3x=80 \n" ); document.write( ".. \n" ); document.write( "5 yrs ago: \n" ); document.write( "x-5=daughter's age \n" ); document.write( "y-5=woman's age \n" ); document.write( "woman nine times as old as her daughter \n" ); document.write( "y-5=9(x-5) \n" ); document.write( ".. \n" ); document.write( "y+3x=80 \n" ); document.write( "y-5=9(x-5)=9x-45 \n" ); document.write( ".. \n" ); document.write( "y+3x=80 \n" ); document.write( "y-9x=-40 \n" ); document.write( "subtract \n" ); document.write( "12x=120 \n" ); document.write( "x=10 \n" ); document.write( "y=80-3x=50 \n" ); document.write( "daughter's age=10 \n" ); document.write( "woman's age=50 \n" ); document.write( " \n" ); document.write( " |