document.write( "Question 749527: A woman's age added thrice her daughter's age amounts to 80years. Five years ago,she was nine times as old as her daughter. How old is each now? \n" ); document.write( "
Algebra.Com's Answer #456033 by lwsshak3(11628)\"\" \"About 
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A woman's age added thrice her daughter's age amounts to 80years. Five years ago,she was nine times as old as her daughter. How old is each now?
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\n" ); document.write( "Now:
\n" ); document.write( "let x=daughter's age
\n" ); document.write( "let y=woman's age
\n" ); document.write( "y+3x=80
\n" ); document.write( "..
\n" ); document.write( "5 yrs ago:
\n" ); document.write( "x-5=daughter's age
\n" ); document.write( "y-5=woman's age
\n" ); document.write( "woman nine times as old as her daughter
\n" ); document.write( "y-5=9(x-5)
\n" ); document.write( "..
\n" ); document.write( "y+3x=80
\n" ); document.write( "y-5=9(x-5)=9x-45
\n" ); document.write( "..
\n" ); document.write( "y+3x=80
\n" ); document.write( "y-9x=-40
\n" ); document.write( "subtract
\n" ); document.write( "12x=120
\n" ); document.write( "x=10
\n" ); document.write( "y=80-3x=50
\n" ); document.write( "daughter's age=10
\n" ); document.write( "woman's age=50
\n" ); document.write( "
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