document.write( "Question 749505: the sum of three numbers is 66. the third number is 9 more than the first. the second number is 3 times the third. what are the numbers? \n" ); document.write( "
Algebra.Com's Answer #456016 by timvanswearingen(106)\"\" \"About 
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Let x represent the third number. Then the first number is x-9 and the second number is 3x.\r
\n" ); document.write( "\n" ); document.write( "Now, the sum of the numbers is 66, so set up an equation:\r
\n" ); document.write( "\n" ); document.write( "\"%28x-9%29%2B3x%2Bx=66\"\r
\n" ); document.write( "\n" ); document.write( "Combine like terms:\r
\n" ); document.write( "\n" ); document.write( "\"5x-9=66\"\r
\n" ); document.write( "\n" ); document.write( "Add 9 to both sides:\r
\n" ); document.write( "\n" ); document.write( "\"5x=75\"\r
\n" ); document.write( "\n" ); document.write( "Divide both sides by 5:\r
\n" ); document.write( "\n" ); document.write( "\"x=15\"\r
\n" ); document.write( "\n" ); document.write( "Thus, the third number is 15. The second was 3x, so 3*15=45. The second number is 45. The first number was x-9, so 15-9=6. The first number is 6. The numbers are 6, 45, and 15.
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