document.write( "Question 749505: the sum of three numbers is 66. the third number is 9 more than the first. the second number is 3 times the third. what are the numbers? \n" ); document.write( "
Algebra.Com's Answer #456016 by timvanswearingen(106)![]() ![]() You can put this solution on YOUR website! Let x represent the third number. Then the first number is x-9 and the second number is 3x.\r \n" ); document.write( "\n" ); document.write( "Now, the sum of the numbers is 66, so set up an equation:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Combine like terms:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add 9 to both sides:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Divide both sides by 5:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Thus, the third number is 15. The second was 3x, so 3*15=45. The second number is 45. The first number was x-9, so 15-9=6. The first number is 6. The numbers are 6, 45, and 15. \n" ); document.write( " |