document.write( "Question 749467: What are the x-intercepts of a parabola witha vertex (4,-1) and y intercept of (0,15) with answer in the form (x1,y1), (x2,y2) \n" ); document.write( "
Algebra.Com's Answer #456011 by josgarithmetic(39620)\"\" \"About 
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Checking how the vertex and the y intercept are arranged on a graph, we can understand that the parabola opens upward, having the vertex as a minimum.\r
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\n" ); document.write( "\n" ); document.write( "\"y=a%28x-h%29%5E2%2Bk\" standard form in which \"a%3E0\".
\n" ); document.write( "Using your vertex coordinates,
\n" ); document.write( "\"y=a%28x-4%29%5E2-1\"\r
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\n" ); document.write( "\n" ); document.write( "The given y intercept point allows the equation, \"15=a%280-4%29%5E2-1\"
\n" ); document.write( "\"15=a%2A16-1\"
\n" ); document.write( "\"16=a%2A16\"
\n" ); document.write( "\"a=1\"\r
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\n" ); document.write( "\n" ); document.write( "Standard form equation is then specifically \"y=1%2A%28x-4%29%5E2-1\"
\n" ); document.write( "or simply
\n" ); document.write( "\"highlight%28y=%28x-4%29%5E2-1%29\"\r
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\n" ); document.write( "\n" ); document.write( "From that standard form equation, you can finish finding the x intercepts on your own. Just let y = 0 and solve for x. \"%28x-4%29%5E2-1=0\".
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