document.write( "Question 749398: how do i solve $\"+ln%28x-1%29-ln%28x%2B1%29=1+\"$ \n" ); document.write( "

Algebra.Com's Answer #455949 by Alan3354(69443) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"+ln%28x-1%29-ln%28x%2B1%29=1+\"$
\n" ); document.write( " $\"+ln%28%28x-1%29%2F%28x%2B1%29%29+=+1+\"$
\n" ); document.write( " $\"+ln%28%28x-1%29%2F%28x%2B1%29%29+=+ln%28e%29\"$
\n" ); document.write( " $\"%28x-1%29%2F%28x%2B1%29+=+e\"$
\n" ); document.write( "x - 1 = ex + e
\n" ); document.write( "x - ex = 1 + e
\n" ); document.write( "x(1 - e) = 1 + e
\n" ); document.write( "x = (1 + e)/(1 - e)
\n" ); document.write( "---------
\n" ); document.write( "1 - e is negative --> x is negative.
\n" ); document.write( "--> ln(x-1) is ln(negative)
\n" ); document.write( "--> no solution.
\n" ); document.write( " \n" ); document.write( "

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