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document.write( "a total of R9000 was invested in two funds. one fund pays 5% interest and the other funs pays 6% interest annually. the combined annual interest is R510. work out how much of the money was invested in each fund \n" );
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Algebra.Com's Answer #455945 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! .06x+.05(9000-x)=510 \n" ); document.write( ".06x+450-.05x=510 \n" ); document.write( ".01x=510-450 \n" ); document.write( ".01x=60 \n" ); document.write( "x=60/.01 \n" ); document.write( "x=$6,000 invested @ 6%. \n" ); document.write( "9,000-6,000=$3,000 invested @ 5%. \n" ); document.write( "Proof: \n" ); document.write( ".06*6,000+.05*3,000=510 \n" ); document.write( "360+150=510 \n" ); document.write( "510=510 \n" ); document.write( " |