document.write( "Question 749438: \r
\n" ); document.write( "\n" ); document.write( "a total of R9000 was invested in two funds. one fund pays 5% interest and the other funs pays 6% interest annually. the combined annual interest is R510. work out how much of the money was invested in each fund
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Algebra.Com's Answer #455945 by checkley79(3341)\"\" \"About 
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.06x+.05(9000-x)=510
\n" ); document.write( ".06x+450-.05x=510
\n" ); document.write( ".01x=510-450
\n" ); document.write( ".01x=60
\n" ); document.write( "x=60/.01
\n" ); document.write( "x=$6,000 invested @ 6%.
\n" ); document.write( "9,000-6,000=$3,000 invested @ 5%.
\n" ); document.write( "Proof:
\n" ); document.write( ".06*6,000+.05*3,000=510
\n" ); document.write( "360+150=510
\n" ); document.write( "510=510
\n" ); document.write( "
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