document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=749356>Question 749356</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of a,b and c is 14. if 9a + 8b + 6c = 101, what is the value of 2a + b -c? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #455917 by </B><A HREF=/tutors/aboutme.mpl?userid=tommyt3rd><B>tommyt3rd(5050)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tommyt3rd><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tommyt3rd><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=455917\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 9a + 8b + 6c = 101 and a+b+c=14  so if we multiply every term by 7 we get:   7a+7b+7c=98\r<BR>\n" );
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document.write( "and if we subtract the result from the first equation we get 2a+b-c=3\r<BR>\n" );
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document.write( "so it's 3\r<BR>\n" );
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document.write( ":) </SPAN>\n" );
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