document.write( "Question 749223: Solution A is 12% acid and Solution B is 4% acid. If a technician wants to mi them to make 60 liters of Solution C which is 10% acid, how many liters of each should be mixed together? \n" ); document.write( "

Algebra.Com's Answer #455908 by josgarithmetic(39620) $\"\"$ $\"About$

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{amount of acid from A plus amount of acid from B}/{volume of solution C} = {concentration of solution C}\r
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\n" ); document.write( "\n" ); document.write( "H = 12%, for solution A
\n" ); document.write( "L = 4%, for solution B
\n" ); document.write( "T = 10 %, wanted as solution C
\n" ); document.write( "M = 60 liters solution C
\n" ); document.write( "u = volume to use solution A
\n" ); document.write( "v = volume to use solution B\r
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\n" ); document.write( "\n" ); document.write( " $\"%28Lu%2BHv%29%2FM=T\"$
\n" ); document.write( " $\"u%2Bv=M\"$ \r
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\n" ); document.write( "\n" ); document.write( "Solve the system for u and v, and then substitute the known values to compute u and v. \n" ); document.write( "

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