document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=749269>Question 749269</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One cylinder with a diameter of 1 foot and a height of 2.75ft. Solve for total surface area.\r<BR>\n" );
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document.write( "I estimated to be 15.75ft. but i'm sure it's wrong. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #455893 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=455893\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One cylinder with a diameter of 1 foot and a height of 2.75ft. Solve for total surface area. <BR>\n" );
document.write( "I estimated to be 15.75ft.<BR>\n" );
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document.write( "Total surface area = side area + top area + bottom area.<BR>\n" );
document.write( "------<BR>\n" );
document.write( "Perimeter = pi*d = pi feet<BR>\n" );
document.write( "radius = 1/2 feet<BR>\n" );
document.write( "area of base = area of top = pi(1/2)^2 = (1/4)pi sq ft<BR>\n" );
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document.write( "Total surface area = 2.75*pi + (1/4)(pi) + (1/4)pi = 3.25pi sq. ft.<BR>\n" );
document.write( "---------------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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