document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=749196>Question 749196</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Lucy bought a car for $23,000. The value of the car depreciates at about 17% each year. When will the value of the car be $10000? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #455839 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=455839\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Lucy bought a car for $23,000. The value of the car depreciates at about 17% each year. When will the value of the car be $10000?<BR>\n" );
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document.write( "Each year the car is worth 83% of its previous year's worth.<BR>\n" );
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document.write( "Solve 10,000 = 23000(0.83)^k<BR>\n" );
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document.write( "(0.83)^k = 10/23<BR>\n" );
document.write( "k = [log(10/23)]/[log(0.83)] = <BR>\n" );
document.write( "k = 4.47 years<BR>\n" );
document.write( "====================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "==================== </SPAN>\n" );
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