document.write( "Question 749187: If logx-2 125 = 3, find x \n" ); document.write( "
Algebra.Com's Answer #455830 by stanbon(75887)\"\" \"About 
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If logx-2 125 = 3, find x
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\n" ); document.write( "log(x-2) [125] = 3
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\n" ); document.write( "125 = (x-2)^3
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\n" ); document.write( "(x-3)^3- 5^3 = 0
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\n" ); document.write( "One of the factors is (x-3)-5
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\n" ); document.write( "So, (x-3)-5 = 0
\n" ); document.write( "x-8 = 0
\n" ); document.write( "x = 8
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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