document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=749079>Question 749079</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A survey is being planned to estimate, with a 98% confidence interval, the mean amount of time per week that seniors spend watching television. The population standard deviation is known to be 5.2 hours. What sample size will be required to obtain an estimate that is within 0.5 hours of the population mean? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #455796 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=455796\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A survey is being planned to estimate, with a 98% confidence interval, the mean amount of time per week that seniors spend watching television. The population standard deviation is known to be 5.2 hours. What sample size will be required to obtain an estimate that is within 0.5 hours of the population mean?<BR>\n" );
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document.write( "Since E = z,<BR>\n" );
document.write( "n = [z*s/E]^2<BR>\n" );
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document.write( "n = [2.3263*5.2/(1/2)]^2<BR>\n" );
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document.write( "n = 586 when rounded up<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "============= </SPAN>\n" );
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