document.write( "Question 749122: If the floor of a room is a rectangle and it has a perimeter of 22 meters and area of 24 square meters what would be the length and width of this room? How do I calculate?
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Algebra.Com's Answer #455782 by Cromlix(4381)\"\" \"About 
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Perimeter = 2 * length + 2 * width
\n" ); document.write( "Area = length * width
\n" ); document.write( "If we make length = x and width = y
\n" ); document.write( "then Perimeter = 2x + 2y
\n" ); document.write( " Area = xy
\n" ); document.write( "Make two equations:\r
\n" ); document.write( "\n" ); document.write( " 2x + 2y = 22...1
\n" ); document.write( " xy = 24...2\r
\n" ); document.write( "\n" ); document.write( "Rearrange xy = 24 => x = 24/y
\n" ); document.write( "Substitute x = 24/y into (1)\r
\n" ); document.write( "\n" ); document.write( " 2(24/y) + 2y = 22
\n" ); document.write( " 48/y + 2y = 22\r
\n" ); document.write( "\n" ); document.write( " Take to one denominator - y\r
\n" ); document.write( "\n" ); document.write( " 48 + 2y^2 = 22y
\n" ); document.write( "Sort out 2y^2 - 22y + 48 = 0
\n" ); document.write( " divide by 2
\n" ); document.write( " y^2 - 11y + 24 = 0
\n" ); document.write( " (y - 3)(y - 8) =0\r
\n" ); document.write( "\n" ); document.write( "So y = 3 or y = 8
\n" ); document.write( "Substituting in 2x + 2y = 22
\n" ); document.write( " 2x + 2(3) = 22
\n" ); document.write( " 2x = 22 - 6
\n" ); document.write( " 2x = 16
\n" ); document.write( " x = 8
\n" ); document.write( " 2x + 2y = 22
\n" ); document.write( " 2x + 16 = 22
\n" ); document.write( " 2x = 22 - 16
\n" ); document.write( " 2x = 6
\n" ); document.write( " x = 3\r
\n" ); document.write( "\n" ); document.write( " So either length is 8m and width is 3m
\n" ); document.write( " or length is 3m and width is 8m
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