document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=65059>Question 65059</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If 6 men can do a piece of work in 14 days, how many men are needed to do the same work in 21 days? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #45578 by </B><A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><B>tutorcecilia(2152)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tutorcecilia><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=45578\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if 6 men/14 days than, than x men/21 days [set-up as a proportion problem]<BR>\n" );
document.write( "6 men/14 days = x men/21 days [set the ratios equal to each other and cross-multiply]<BR>\n" );
document.write( ".<BR>\n" );
document.write( "(6)(21)=14x<BR>\n" );
document.write( "126=14x [solve for x]<BR>\n" );
document.write( "x=9<BR>\n" );
document.write( ".<BR>\n" );
document.write( "checking:<BR>\n" );
document.write( "6 men/14 days = 9 men/21 days<BR>\n" );
document.write( "126=126 [checks out]\r<BR>\n" );
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