document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=749112>Question 749112</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do I solve ln (5-x) =12 ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #455775 by </B><A HREF=/tutors/aboutme.mpl?userid=timvanswearingen><B>timvanswearingen(106)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=timvanswearingen><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=timvanswearingen><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=455775\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Natural Log has base e, so you'll raise e to both sides of the equation:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=ln+%285-x%29+=12 ALIGN=MIDDLE  ALT=\"ln+%285-x%29+=12\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=e%5E%28ln+%285-x%29%29+=+e%5E12 ALIGN=MIDDLE  ALT=\"e%5E%28ln+%285-x%29%29+=+e%5E12\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "The e and ln basically cancel each other out, so you've got:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5-x+=+e%5E12 ALIGN=MIDDLE  ALT=\"5-x+=+e%5E12\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Now just solve for x:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5-x+=+e%5E12 ALIGN=MIDDLE  ALT=\"5-x+=+e%5E12\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Add x to both sides:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5+=+e%5E12%2Bx ALIGN=MIDDLE  ALT=\"5+=+e%5E12%2Bx\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Subtract e^12 from both sides:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5-e%5E12+=+x ALIGN=MIDDLE  ALT=\"5-e%5E12+=+x\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "That is an exact answer.  If you want an approximated answer, just evaluate that and round to whichever place you need to. </SPAN>\n" );
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