document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=749099>Question 749099</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Candy and Delvis are riding bicycles in the same direction. Candy is traveling at a speed of 6 miles per hour, and Delvis is traveling at a speed of 8 miles per hour. In 3 hours what is the distance between them (assuming that they began at the same point and time)? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #455771 by </B><A HREF=/tutors/aboutme.mpl?userid=timvanswearingen><B>timvanswearingen(106)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=timvanswearingen><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=timvanswearingen><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=455771\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Every hour that goes by, Delvis is going 2 more miles.  \r<BR>\n" );
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document.write( "They will be 6 miles apart.\r<BR>\n" );
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document.write( "Alternately, Candy is going 6mi/h.  Multiply by the number of hours to see how far she goes.  6mi/h * 3 h = 18 miles.\r<BR>\n" );
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document.write( "Delvis is going 8mi/h.  Multiply by the number of hours to see how far she goes.  8mi/h * 3 h = 24 miles.  \r<BR>\n" );
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document.write( "From here, hopefully you can see that they are 6 miles apart.  24-18=6 </SPAN>\n" );
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