document.write( "Question 748988: the height of a triangle measures 9 inches more then its base, the area is 45 square inches, the measures of the base and height of the triangle?how do i find \n" ); document.write( "
Algebra.Com's Answer #455733 by checkley79(3341)\"\" \"About 
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AREA=BH/2
\n" ); document.write( "H=B+9
\n" ); document.write( "45=B(B+9)/2
\n" ); document.write( "45=(B^2+9B)/2 CROSS MULTIPLY.
\n" ); document.write( "45*2=B^2+9B
\n" ); document.write( "90=B^2+9B
\n" ); document.write( "B^2+9B-90=0
\n" ); document.write( "(B+15)(B-6)=0
\n" ); document.write( "B-6=0
\n" ); document.write( "B=6 ANS. FOR THE BASE.
\n" ); document.write( "H=6+9=15 ANS. FOR THE HEIGHT.
\n" ); document.write( "PROOF:
\n" ); document.write( "45=6*15/2
\n" ); document.write( "45=90/2
\n" ); document.write( "45=45
\n" ); document.write( "
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