document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=749008>Question 749008</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am having trouble with this word problem.<BR>\n" );
document.write( "      Ace Construction Company rents a bulldozer for $100.00 per day plus $50.00 per hour it is in use. If the bulldozer rental bill on April was $480.00, how many hours was the bulldozer used.<BR>\n" );
document.write( "     I worked it out as x+y=480 x=per hour y=per day and y=50x-$100 but I keep getting a decimal and it dont add up  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #455726 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=455726\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 100+50x=480<BR>\n" );
document.write( "5x=480-100<BR>\n" );
document.write( "50x=380<BR>\n" );
document.write( "x=380/50<BR>\n" );
document.write( "x=7.6 hours of use IF the rental was for only 1 day.<BR>\n" );
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