document.write( "Question 748992: The camera Melissa wanted for her birthday is on sale at 41% off the usual price. The amount of the discount is $155.80. What was the original price of the camera? \n" ); document.write( "
Algebra.Com's Answer #455714 by timvanswearingen(106)\"\" \"About 
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If the discount was $155.80, then 41% of the original price is $155.80. Let p be the original price:\r
\n" ); document.write( "\n" ); document.write( "\"%280.41%29%2Ap+=+155.80\"\r
\n" ); document.write( "\n" ); document.write( "Divide both sides by 0.41:\r
\n" ); document.write( "\n" ); document.write( "\"p=380\"\r
\n" ); document.write( "\n" ); document.write( "The original price of the camera was $380
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