document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=748587>Question 748587</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help me solve logx square root 3/3= -1/2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #455677 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=455677\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> solve logx square root 3/3= -1/2<BR>\n" );
document.write( "log(x&#8730;3/3)=-1/2<BR>\n" );
document.write( "10^(-1/2)=x&#8730;3/3<BR>\n" );
document.write( "0.3162=x&#8730;3/3<BR>\n" );
document.write( "&#8730;3x=3*.3162=0.9487<BR>\n" );
document.write( "x=0.9487/&#8730;3=0.5477 </SPAN>\n" );
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