document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=748663>Question 748663</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A particular metal ally A has 20% iron and another alloy B contains 60% iron. How many kilograms of each alloy should be combined to create 80 kg of 52% iron alloy </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #455567 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=455567\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A particular metal alloy A has 20% iron and another alloy B contains 60% iron. How many kilograms of each alloy should be combined to create 80 kg of 52% iron alloy<BR>\n" );
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document.write( "iron + iron = iron<BR>\n" );
document.write( "0.20x + 0.60(80-x) = 0.52(80)<BR>\n" );
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document.write( "20x + 60*80 - 60x = 52*80<BR>\n" );
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document.write( "-40x = -8*80<BR>\n" );
document.write( "x = (1/5)80<BR>\n" );
document.write( "x = 16 kg (amt. of 20% alloy needed)<BR>\n" );
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document.write( "80-x = 64 kg (amt. of 60% alloy needed)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( " </SPAN>\n" );
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