document.write( "Question 748607: the circle passes through the point (0,0), (5,0) and (3,3) \n" ); document.write( "
Algebra.Com's Answer #455566 by AnlytcPhil(1810) You can put this solution on YOUR website! the circle passes through the point (0,0), (5,0) and (3,3) \n" ); document.write( " \r\n" ); document.write( "You can do this either by using the general form or the standard form.\r\n" ); document.write( "I'll first do it with the general form:\r\n" ); document.write( "\r\n" ); document.write( "x² + y² + Dx + Ey + F = 0\r\n" ); document.write( "\r\n" ); document.write( "Substitute (x,y) = (0,0)\r\n" ); document.write( "\r\n" ); document.write( "0² + 0² + D(0) + E(0) + F = 0\r\n" ); document.write( " F = 0\r\n" ); document.write( "So we have\r\n" ); document.write( "\r\n" ); document.write( "x² + y² + Dx + Ey + 0 = 0\r\n" ); document.write( " x² + y² + Dx + Ey = 0\r\n" ); document.write( "\r\n" ); document.write( "Substitute (x,y) = (5,0)\r\n" ); document.write( "\r\n" ); document.write( "5² + 0² + D(5) + E(0) = 0\r\n" ); document.write( " 25 + 5D = 0\r\n" ); document.write( " 25 + 5D = 0\r\n" ); document.write( " 5D = -25\r\n" ); document.write( " D = -5\r\n" ); document.write( "\r\n" ); document.write( "So we have:\r\n" ); document.write( "\r\n" ); document.write( " x² + y² + Dx + Ey = 0\r\n" ); document.write( " x² + y² - 5x + Ey = 0\r\n" ); document.write( "\r\n" ); document.write( "Substitute (x,y) = (3,3)\r\n" ); document.write( "\r\n" ); document.write( " x² + y² - 5x + Ey = 0\r\n" ); document.write( "(3)² + (3)² - 5(3) + E(3) = 0\r\n" ); document.write( " 9 + 9 - 15 + 3E = 0\r\n" ); document.write( " 3 + 3E = 0\r\n" ); document.write( " 3E = -3\r\n" ); document.write( " E = -1 \r\n" ); document.write( "\r\n" ); document.write( " x² + y² - 5x + Ey = 0\r\n" ); document.write( " x² + y² - 5x - y = 0\r\n" ); document.write( "\r\n" ); document.write( "------------------------------------------\r\n" ); document.write( "You can also use the standard form equation for a circle:\r\n" ); document.write( "\r\n" ); document.write( " (x - h)² + (y - k)² = r²\r\n" ); document.write( "\r\n" ); document.write( "Substitute (x,y) = (0,0)\r\n" ); document.write( "\r\n" ); document.write( " (0 - h)² + (0 - k)² = r²\r\n" ); document.write( " h² + k² = r²\r\n" ); document.write( "\r\n" ); document.write( "Substitute (x,y) = (5,0)\r\n" ); document.write( "\r\n" ); document.write( " (5 - h)² + (0 - k)² = r²\r\n" ); document.write( " 25 - 10h + h² + k² = r²\r\n" ); document.write( "\r\n" ); document.write( "Substitute (x,y) = (3,3)\r\n" ); document.write( "\r\n" ); document.write( " (3 - h)² + (3 - k)² = r²\r\n" ); document.write( "9 - 6h + h² + 9 - 6k + k² = r²\r\n" ); document.write( " 18 - 6h - 6k + h² + k² = r²\r\n" ); document.write( "\r\n" ); document.write( "So we have this system of equations:\r\n" ); document.write( "\r\n" ); document.write( " h² + k² = r²\r\n" ); document.write( " 25 - 10h + h² + k² = r²\r\n" ); document.write( " 18 - 6h - 6k + h² + k² = r² \r\n" ); document.write( "\r\n" ); document.write( "If we subtract the first equation term by term from each of the\r\n" ); document.write( "other two equations we have:\r\n" ); document.write( "\r\n" ); document.write( " 25 - 10h = 0\r\n" ); document.write( " 18 - 6h - 6k = 0\r\n" ); document.write( "\r\n" ); document.write( "Solving the first for h\r\n" ); document.write( "\r\n" ); document.write( " 25 - 10h = 0\r\n" ); document.write( " -10h = -25 \r\n" ); document.write( " h =\n" ); document.write( " |