document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=748647>Question 748647</A>: <I><SPAN STYLE=\"word-break: break-all;\"> log(x+9)=log(2x-7) \r<BR>\n" );
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document.write( "I do not need the answer so much as how to do this. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #455553 by </B><A HREF=/tutors/aboutme.mpl?userid=timvanswearingen><B>timvanswearingen(106)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=timvanswearingen><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=timvanswearingen><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=455553\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You raise 10 to the power of both sides...the 10 and log cancel out, so you end up with just x+9=2x-7 and you can solve from there.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=10%5Elog%28%28x%2B9%29%29=10%5Elog%28%282x-7%29%29 ALIGN=MIDDLE  ALT=\"10%5Elog%28%28x%2B9%29%29=10%5Elog%28%282x-7%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > \r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2B9=2x-7 ALIGN=MIDDLE  ALT=\"x%2B9=2x-7\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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