document.write( "Question 65033This question is from textbook college algebra
\n" ); document.write( ": Another I have to turn in and I am still having trouble with. HELP!\r
\n" ); document.write( "\n" ); document.write( "Write the expression in terms of the logarithms of x and y:\r
\n" ); document.write( "\n" ); document.write( "log 5x^2/square root of y\r
\n" ); document.write( "\n" ); document.write( "y is under a square root symbol. Hope that is clear enough. Thanks!
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Algebra.Com's Answer #45554 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Write the expression in terms of the logarithms of x and y:
\n" ); document.write( "log 5x^2/square root of y
\n" ); document.write( "y is under a square root symbol
\n" ); document.write( "--------
\n" ); document.write( "Using the quotient rule you get:
\n" ); document.write( "= [log 5x^2] - [log sqrt y]
\n" ); document.write( "Using the product rule and the power rule you get:
\n" ); document.write( "=[log 5 + 2log x] - [(1/2)log y]
\n" ); document.write( "Simplify to get:
\n" ); document.write( "=log 5 + 2logx -(1/2)log y
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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