document.write( "Question 748571: Find 3 consecutive integers such that 5 times the 2nd equals twice the sum of the 1st and 3rd. \n" ); document.write( "
Algebra.Com's Answer #455517 by timvanswearingen(106)\"\" \"About 
You can put this solution on YOUR website!
Let the smallest integer be x, then the middle is x+1 and the largest is x+2.\r
\n" ); document.write( "\n" ); document.write( "5 times the 2nd equals twice the sum of the 1st and 3rd:\r
\n" ); document.write( "\n" ); document.write( "\"5%28x%2B1%29=2%28x%2B%28x%2B2%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"5x%2B5=2%282x%2B2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"5x%2B5=4x%2B4\"\r
\n" ); document.write( "\n" ); document.write( "\"x%2B5=4\"\r
\n" ); document.write( "\n" ); document.write( "\"x=+-1\"\r
\n" ); document.write( "\n" ); document.write( "The other numbers are x+1 and x+2, so they are 0 and 1.
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