document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=65026>Question 65026</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Having difficulty with two problems:\r<BR>\n" );
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document.write( "2^(x+3)=5^x\r<BR>\n" );
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document.write( "and\r<BR>\n" );
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document.write( "10e^(3x-7)=5\r<BR>\n" );
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document.write( "For 2^(x+3)=5^x I converted it into a log with base of 2\r<BR>\n" );
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document.write( "log(base2) (2^(x+3)) = log(base2) 5^x\r<BR>\n" );
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document.write( "x+3=log(base2) 5^x<BR>\n" );
document.write( "x=log(base2) (5^x) - 3\r<BR>\n" );
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document.write( "and get stuck there.. am I even on the right track? As for the 2nd one, I've made no progress at all.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #45550 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=45550\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Having difficulty with two problems: <BR>\n" );
document.write( "2^(x+3)=5^x <BR>\n" );
document.write( "Take the log of both sides to get:<BR>\n" );
document.write( "(x+3)log2 = xlog5<BR>\n" );
document.write( "Distribute to get:<BR>\n" );
document.write( "(log2)x + 3log2 = xlog5<BR>\n" );
document.write( "Get the x-terms together as follows:<BR>\n" );
document.write( "(log2-log5)x=-3log2<BR>\n" );
document.write( "Evaluate to get:<BR>\n" );
document.write( "-0.39794..x=-0.903089987..<BR>\n" );
document.write( "Divide to get:<BR>\n" );
document.write( "x=2.269...<BR>\n" );
document.write( "-----------------<BR>\n" );
document.write( "and <BR>\n" );
document.write( "10e^(3x-7)=5 <BR>\n" );
document.write( "Divide by 10 to get:<BR>\n" );
document.write( "e^(3x-7)=(1/2)<BR>\n" );
document.write( "Take the natural log of both sides to get:<BR>\n" );
document.write( "3x-7=ln(1/2)<BR>\n" );
document.write( "3x=-0.693147...+7<BR>\n" );
document.write( "3x=6.30685...<BR>\n" );
document.write( "x=2.10228...<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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