document.write( "Question 748251: Use the given information to find sin 2theta, cos 2theta, and tan 2theta.
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document.write( "#1) cos theta = 4/5 , 0 deg < theta < 90 deg\r
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document.write( "#2) sin theta = 1/3, 0 < theta < pi/2 \n" );
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Algebra.Com's Answer #455496 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Use the given information to find sin 2theta, cos 2theta, and tan 2theta. \n" ); document.write( "#1) cos theta = 4/5 , 0 deg < theta < 90 deg \n" ); document.write( "#2) sin theta = 1/3, 0 < theta < pi/2 \n" ); document.write( "*** \n" ); document.write( "#1 \n" ); document.write( "cos(x)=4/5 \n" ); document.write( "sin(x)=3/5 (3-4-5) right triangle \n" ); document.write( "tan(x)=sin(x)/cos(x)=3/4 \n" ); document.write( "... \n" ); document.write( "sin(2x)=2sin(x)cos(x)=2*3/5*4/5=24/25 \n" ); document.write( "cos(2x)=cos^2(x)-sin^2(x)=16/25-9/25=7/25 \n" ); document.write( "tan(2x)=(2tan(x))/(1-tan^2(x)=(6/4)/(1-(9/16))=(24/16)/(7/16)=24/7 \n" ); document.write( ".. \n" ); document.write( "#2 \n" ); document.write( "sin(x)=1/3 \n" ); document.write( "adjacent side=√(3^2)-1)=√8 \n" ); document.write( "cos(x)=√8/3 \n" ); document.write( "tan(x)=1/√8=√8/8=√2/4 \n" ); document.write( "... \n" ); document.write( "sin(2x)=2sin(x)cos(x)=2*1/3*√8/3=2√8/9 \n" ); document.write( "cos(2x)=cos^2(x)-sin^2(x)=8/9-1/9=7/9 \n" ); document.write( "tan(2x)=(2tan(x))/(1-tan^2(x))=(√2/2)/(1-(1/8))=(√2/2)/(7/8)=4√2/7 \n" ); document.write( ".. \n" ); document.write( " |