document.write( "Question 748158: Crisner is 3 years older than her niece Josephine. In 7 years she will be six seventh of her age. How old are they? \n" ); document.write( "
Algebra.Com's Answer #455473 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! ): Crisner is 3 years older than her niece Josephine. \n" ); document.write( " In 7 years she will be six seventh of her age. \n" ); document.write( " How old are they? \n" ); document.write( ": \n" ); document.write( "Let c = C's age now \n" ); document.write( "Let j = J's age \n" ); document.write( "; \n" ); document.write( "Write an equation for each statement \n" ); document.write( ": \n" ); document.write( "\"): Crisner is 3 years older than her niece Josephine.\" \n" ); document.write( "c = j + 3 \n" ); document.write( ": \n" ); document.write( "\"In 7 years she will be six seventh of her age.\" \n" ); document.write( "j + 7 = \n" ); document.write( "Get rid of that annoying fraction, mult both sides by 7 \n" ); document.write( "7(j+7) = 6(c+7) \n" ); document.write( "7j + 49 = 6c + 42 \n" ); document.write( "7j = 6c + 42 - 49 \n" ); document.write( "7j = 6c - 7 \n" ); document.write( "replace c with (j+3) from the 1st statement \n" ); document.write( "7j = 6(j+3) - 7 \n" ); document.write( "7j = 6j + 18 - 7 \n" ); document.write( "7j - 6j = 11 \n" ); document.write( "j = 11 yrs is J's age \n" ); document.write( "then \n" ); document.write( "11 + 3 = 14 yrs is C's age \n" ); document.write( "; \n" ); document.write( "; \n" ); document.write( "see if that works \n" ); document.write( "j + 7 = \n" ); document.write( "11 + 7 = \n" ); document.write( "18 = \n" ); document.write( "7 cancels into 21 \n" ); document.write( "18 = 6(3) \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |