document.write( "Question 748396: a driver completed a trip in 6 hours. if his average speed had been ten kph more, the trip would have taken one hour less. what is the average speed for the trip? \n" ); document.write( "
Algebra.Com's Answer #455465 by josgarithmetic(39618)![]() ![]() ![]() You can put this solution on YOUR website! Letting r = average speed for the trip,\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "________________rate___________time__________distance \n" ); document.write( "Actual___________r______________6____________ \n" ); document.write( "Fictional________r+10___________5____________ \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Immediately filled information were rate and time. Calculated expressions were the distance, giving two different expressions. The distance for \"Actual\" and for \"Fictional\" are equal. That is the same distance done at different rates.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |