document.write( "Question 748367: IF I throw a bal from a height of 25 feet at a velocity of 18 feet per sec. What is the equation? How long until it hits the ground? What is the max height? \n" ); document.write( "
Algebra.Com's Answer #455459 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Where is the height at time in seconds, is the magnitude of the initial velocity, is the angle the initial path makes with the ground, and is the initial height.\r
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\n" ); document.write( "\n" ); document.write( "You didn't specify which way you threw the ball, so if straight up, then . If straight down, the . Somewhere in between -- look it up.\r
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\n" ); document.write( "\n" ); document.write( "Once you have substituted all of your known values, set the function equal to zero -- since the height of ground is zero -- and solve the quadratic equation for .\r
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\n" ); document.write( "\n" ); document.write( "The maximum height is 25 feet if you throw the ball at an angle with the horizontal of anything greater than or equal to . On the other hand, if you throw the ball upward at all, the parabolic arch described by the ball will have a maximum at the vertex of the parabola. For any parabola of the form\r
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\n" ); document.write( "\n" ); document.write( "The -coordinate of the vertex is found by , and that vertex is a maximum whenever the lead coefficient is less than zero. Evaluate your function at to find the value of the maximum.\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "Egw to Beta kai to Sigma
\n" ); document.write( "My calculator said it, I believe it, that settles it
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