document.write( "Question 748315: $25,000 invested in two accounts, one yielding 8% and the other yielding 10%. A total of $2,380.00 in interest was received at the end of the year. How much was invested in each account? \n" ); document.write( "
| Algebra.Com's Answer #455428 by checkley79(3341)      You can put this solution on YOUR website! .10X+.08(25,000-X)=2,380 \n" ); document.write( ".10X+2,000-.08X=2,380 \n" ); document.write( ".02X=2,380-2,000 \n" ); document.write( ".02X=380 \n" ); document.write( "X=380/.02 \n" ); document.write( "X=$19,000 AMOUNT INVESTED @ 10% \n" ); document.write( "25,000-19000=$6,000 AMOUNT INVESTED @ 8%. \n" ); document.write( "PROOF: \n" ); document.write( ".10*19,000+.08*6,000=2,380 \n" ); document.write( "1,900+480=2,380 \n" ); document.write( "2,380=2,380 \n" ); document.write( " |