document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=748273>Question 748273</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help? I am having trouble with mixture formulas? How many kg of pure silver must be added to 56.75 kg of an alloy containing 9 percent to raise it to 15 percent? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #455422 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=455422\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .09*56.75+X=.15(56.75+X)<BR>\n" );
document.write( "5.1075+X=8.5125+.15X<BR>\n" );
document.write( "X-.15X=8.5125-5.1075<BR>\n" );
document.write( ".85X=3.405<BR>\n" );
document.write( "X=3.405/.85<BR>\n" );
document.write( "X=4.006 kg. OF PURE SILVER IS USED.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( ".09*56.75+4.006=.15(56.75+4.006<BR>\n" );
document.write( "5.1075+4.006=.15(56.75+4.006)<BR>\n" );
document.write( "9.1135=.15*60.756<BR>\n" );
document.write( "9.1135=9.1134<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );