document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=748235>Question 748235</A>: <I><SPAN STYLE=\"word-break: break-all;\"> This doesn't make sense...Someone help me please!The equation is:  <BR>\n" );
document.write( "r^3=2r^2+15r </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #455381 by </B><A HREF=/tutors/aboutme.mpl?userid=tinbar><B>tinbar(133)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tinbar><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=455381\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> r^3=2r^2+15r<BR>\n" );
document.write( "r^3 - 2r^2 - 15r = 0<BR>\n" );
document.write( "r(r^2 - 2r - 15) = 0\r<BR>\n" );
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document.write( "Therefore r = 0, is one solution and whenever (r^2 - 2r - 15) = 0, the equation is satisfied.\r<BR>\n" );
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document.write( "r^2 - 2r - 15 = 0<BR>\n" );
document.write( "(r-5)(r+3) = 0\r<BR>\n" );
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document.write( "Therefore, r = 5 and r = -3 are also solutions.\r<BR>\n" );
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document.write( "Finally, r = 0, r = -3, and r = 5 are the solutions to the original equation. </SPAN>\n" );
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