document.write( "Question 64865This question is from textbook algebra 1
\n" ); document.write( ": solve for x and y\r
\n" ); document.write( "\n" ); document.write( "3x+1=-7y\r
\n" ); document.write( "\n" ); document.write( "6x+7y=0
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Algebra.Com's Answer #45537 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
solve for x and y
\n" ); document.write( "(1) 3x+1=-7y
\n" ); document.write( "(2) 6x+7y=0\r
\n" ); document.write( "\n" ); document.write( "From (2), if we subtract 7y from both sides. we see that 6x=-7y or\r
\n" ); document.write( "\n" ); document.write( "(2a) -7y=6x\r
\n" ); document.write( "\n" ); document.write( "substituting for -7y in (1) we get:\r
\n" ); document.write( "\n" ); document.write( "3x+1=6x or subtracting 3x from both sides, we have:
\n" ); document.write( "6x-3x=1
\n" ); document.write( "3x=1
\n" ); document.write( "x=1/3\r
\n" ); document.write( "\n" ); document.write( "substituting in (2a):
\n" ); document.write( "-7y=6(1/3)=2\r
\n" ); document.write( "\n" ); document.write( "y=(-2/7)\r
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\n" ); document.write( "\n" ); document.write( "ck
\n" ); document.write( "Substitute for x & y in (1):
\n" ); document.write( "3x+1=-7y
\n" ); document.write( "3(1/3)+1=-7(-2/7)=
\n" ); document.write( "1+1=2
\n" ); document.write( "2=2\r
\n" ); document.write( "\n" ); document.write( "Substitute for x & y in (2):
\n" ); document.write( "6x+7y=0
\n" ); document.write( "6(1/3)+7(-2/7)=0
\n" ); document.write( "2-2=0
\n" ); document.write( "0=0\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps. Happy holidays------ptaylor
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