document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=748140>Question 748140</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A principal of $3800 is invested at 6.25% interest, compounded annually. How many years will it take to accumulate $6000 or more in the account?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #455340 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=455340\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A principal of $3800 is invested at 6.25% interest, compounded annually. How many years will it take to accumulate $6000 or more in the account? <BR>\n" );
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document.write( "A(t) = P(1+(r/n))^(nt)<BR>\n" );
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document.write( "6000 = 3800(1+(0.0625/1))^(1*t)<BR>\n" );
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document.write( "1.5789 = (1.0625)^t<BR>\n" );
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document.write( "t = log(1.5789)/log(1.0625) <BR>\n" );
document.write( "t >= 7.53 years<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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