document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=65022>Question 65022</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I cant figure out this word problem:  Five times a number is 21 less than twice the opposite of the number. What is the number? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #45534 by </B><A HREF=/tutors/aboutme.mpl?userid=303795><B>303795(602)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=303795><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=45534\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the required number x.<BR>\n" );
document.write( "Five times the number is 5x.<BR>\n" );
document.write( "If this is 21 less than something then add on 21 so it will be equal to it.<BR>\n" );
document.write( "5x + 21 =<BR>\n" );
document.write( "The opposite of the number is (-x). Twice that will be 2*(-x)<BR>\n" );
document.write( "So 5x + 21 = 2*(-x)\r<BR>\n" );
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document.write( "5x + 21 = -2x<BR>\n" );
document.write( "Add 2x to both sides of the equation<BR>\n" );
document.write( "5x + 26  + 2x = -2x + 2x<BR>\n" );
document.write( "7x + 21 = 0<BR>\n" );
document.write( "Subtract 21 from each side of the equation<BR>\n" );
document.write( "7x + 21 - 21 = 0 - 21<BR>\n" );
document.write( "7x = -21<BR>\n" );
document.write( "x=-21/7<BR>\n" );
document.write( "x=-3 <BR>\n" );
document.write( "Check if this meets the original conditions. </SPAN>\n" );
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