document.write( "Question 738852: Please help me solve for x.
\n" ); document.write( "(square root of 2x-14) - (the square root of x) + 4 = 3
\n" ); document.write( "

Algebra.Com's Answer #455321 by tommyt3rd(5050)\"\" \"About 
You can put this solution on YOUR website!
\"sqrt%282x-14%29+-+sqrt%28x%29+%2B+4+=+3\"\r
\n" ); document.write( "\n" ); document.write( "\"sqrt%282x-14%29-sqrt%282x-14%29+-+sqrt%28x%29+%2B+4-3+=3-3+-sqrt%282x-14%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"1+-+sqrt%28x%29++=-sqrt%282x-14%29\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "squaring...\r
\n" ); document.write( "\n" ); document.write( "\"%281+-+sqrt%28x%29+%29%5E2+=%28-sqrt%282x-14%29%29%5E2\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "rearranging then squaring again...
\n" ); document.write( "\"%0D%0A1-2sqrt%28x%29%2Bx=2x-14%0D%0A\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%0D%0A-2sqrt%28x%29=x-15%0D%0A\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%0D%0A%282sqrt%28x%29%29%5E2=%28x-15%29%5E2%0D%0A\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%0D%0A4x=x%5E2-30x%2B225%0D%0A\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%0D%0Ax%5E2-34x%2B225=0%0D%0A\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%28x-9%29%28x-25%29=0\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "After testing we find that x=25 does not work so our only solution is x=9\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( ":)
\n" ); document.write( "
\n" );