document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=743309>Question 743309</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 4yd longer than its width. <BR>\n" );
document.write( "If the perimeter of the rectangle is 28yd , find its area. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #455315 by </B><A HREF=/tutors/aboutme.mpl?userid=tommyt3rd><B>tommyt3rd(5050)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tommyt3rd><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tommyt3rd><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=455315\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> l=w+4<BR>\n" );
document.write( "P=2(l+w)=28\r<BR>\n" );
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document.write( "or l+w=14 and so l=14-w\r<BR>\n" );
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document.write( "which leads us to\r<BR>\n" );
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document.write( "w+4=14-w\r<BR>\n" );
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document.write( "w+w+4-4=14-4-w+w\r<BR>\n" );
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document.write( "2w=10\r<BR>\n" );
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document.write( "and w=5\r<BR>\n" );
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document.write( "therefore l=5+4=9\r<BR>\n" );
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document.write( "and that means A=lw=(9)(5)=45 square yards\r<BR>\n" );
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document.write( ":) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );