document.write( "Question 748049: Please help. Ive been stuck on this question for a while and can't seem to figure it out. The question is, \"Find an equation of the line that passes through (4, 2); perpendicular to 2x-3y=2\" \n" ); document.write( "
Algebra.Com's Answer #455310 by nerdybill(7384)\"\" \"About 
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Find an equation of the line that passes through (4, 2); perpendicular to 2x-3y=2
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\n" ); document.write( "find slope of:
\n" ); document.write( "2x-3y=2
\n" ); document.write( "2x=3y+2
\n" ); document.write( "2x-2=3y
\n" ); document.write( "(2/3)x-2/3=y
\n" ); document.write( "slope is 2/3
\n" ); document.write( "a line perpendicular must have a slope that is the \"negative reciprocal\": -3/2
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\n" ); document.write( "plug slope (-3/2) and point (4,2) into the \"point-slope form\"
\n" ); document.write( "y - y1 = m(x - x1)
\n" ); document.write( "y - 2 = (-3/2)(x - 4)
\n" ); document.write( "y - 2 = (-3/2)x - (-3/2)4
\n" ); document.write( "y - 2 = (-3/2)x - (-6)
\n" ); document.write( "y - 2 = (-3/2)x + 6
\n" ); document.write( "y = (-3/2)x + 8 (answer)\r
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