document.write( "Question 747992: how to solve Marcus and Will are painting a barn. Marcus paints twice as fast as Will. On the first day, they have worked for 6 h and completed 1/3 of the job when Will gets injured. If Marcus has to complete the rest of the job by himself, how many additional hours will it take him? answer \n" ); document.write( "
Algebra.Com's Answer #455282 by josgarithmetic(39618)![]() ![]() ![]() You can put this solution on YOUR website! This one makes more sense than your almost identical posting. Completed 1/3 of the job and Will gets injured.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Marcus rate, 2/x jobs per hour \n" ); document.write( "Will rate, 1/x jobs per hour. \n" ); document.write( "time working together was 6 hours, and 1/3 of the job was completed.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "When we find \"x\" here, we will know how to compute the rate for each of Marcus and Will.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Finding x: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "RATES OF THE TWO PAINTERS: \n" ); document.write( "Marcus, \n" ); document.write( "Will, \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If Marcus does the rest of the job himself, how long will this take him? Remember, 1/3 of the job was done, so Marcus will do 2/3 of the job. \n" ); document.write( "The situation is a uniform rates situation and so we have \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "His rate is (1/3), so \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |