document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=747967>Question 747967</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangle has a perimeter of 78 feet. If the width is 5 feet less than the length. what are the dimensions ?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #455260 by </B><A HREF=/tutors/aboutme.mpl?userid=FrankM><B>FrankM(1040)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=FrankM><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=FrankM><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=455260\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> W+5=L\r<BR>\n" );
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document.write( "Perimeter is the sum of 4 sides, 2W + 2L\r<BR>\n" );
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document.write( "But L=W+5 so\r<BR>\n" );
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document.write( "78= 2W+2W+10\r<BR>\n" );
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document.write( "78 = 4W + 10\r<BR>\n" );
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document.write( "68= 4W\r<BR>\n" );
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document.write( "W = 17 and L = 22  </SPAN>\n" );
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