document.write( "Question 747846: The length of a rectangle is 2 in. more than twice its width. If the perimeter of the rectangle is 28 in., find the width of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #455186 by Cromlix(4381)\"\" \"About 
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Width = x Length = (2 + 2x)
\n" ); document.write( "Perimeter = 2 * length + 2 + width
\n" ); document.write( " = 2(2 + 2x) + 2x
\n" ); document.write( " = 4 + 4x + 2x
\n" ); document.write( " = 4 + 6x\r
\n" ); document.write( "\n" ); document.write( " Perimeter = 28 ins.
\n" ); document.write( " 4 + 6x = 28 ins.
\n" ); document.write( " 6x = 28 - 4 ins.
\n" ); document.write( " 6x = 24 ins
\n" ); document.write( " x = 4 ins\r
\n" ); document.write( "\n" ); document.write( "Therefore width = 4 ins.
\n" ); document.write( " length= 10ins\r
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