document.write( "Question 747840: Hi i need help with this problem please\r
\n" ); document.write( "\n" ); document.write( "log4(x-4)=3-log(x+8)
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Algebra.Com's Answer #455183 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\"log%284%2Cx-4%29=3-log%28x%2B8%29\"....I guess you have \"log%284%2C%28x%2B8%29%29\"\r
\n" ); document.write( "\n" ); document.write( "if so, then you have\r
\n" ); document.write( "\n" ); document.write( "\"log%284%2C%28x-4%29%29=3-log%284%2C%28x%2B8%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"log%284%2C%28x-4%29%29%2Blog%284%2C%28x%2B8%29%29=3\"\r
\n" ); document.write( "\n" ); document.write( "\"log%28x-4%29%2Flog%284%29%2Blog%28x%2B8%29%2Flog%284%29=3\"\r
\n" ); document.write( "\n" ); document.write( "\"%28log%28x-4%29%2Blog%28x%2B8%29%29%2Flog%284%29=3\"\r
\n" ); document.write( "\n" ); document.write( "\"log%28x-4%29%2Blog%28x%2B8%29=3log%284%29\"\r
\n" ); document.write( "\n" ); document.write( "\"log%28x-4%29%2Blog%28x%2B8%29=log%284%5E3%29\"\r
\n" ); document.write( "\n" ); document.write( "\"log%28%28x-4%29%28x%2B8%29%29=log%2864%29\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x-4%29%28x%2B8%29=64\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B8x-4x-32=64\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B4x-32-64=0\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B4x-96=0\"....write \"4x\" as \"12x-8x\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B12x-8x-96=0\"..group\r
\n" ); document.write( "\n" ); document.write( "\"%28x%5E2%2B12x%29-%288x%2B96%29=0\"\r
\n" ); document.write( "\n" ); document.write( "\"x%28x%2B12%29-8%28x%2B12%29=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x-8%29%28x%2B12%29=0\"\r
\n" ); document.write( "\n" ); document.write( "solutions:\r
\n" ); document.write( "\n" ); document.write( "if \"x-8=0\" => \"x=8\"\r
\n" ); document.write( "\n" ); document.write( "if \"x%2B12=0\" => \"x=-12\"\r
\n" ); document.write( "\n" ); document.write( "your solution is: \"highlight%28x=8%29\"\r
\n" ); document.write( "\n" ); document.write( "recall:\r
\n" ); document.write( "\n" ); document.write( "The logarithmic function\r
\n" ); document.write( "\n" ); document.write( "\"y+=+log%28b%2Cx%29\"\r
\n" ); document.write( "\n" ); document.write( "is the inverse function of the exponential function\r
\n" ); document.write( "\n" ); document.write( "\"x+=+b%5Ey\"\r
\n" ); document.write( "\n" ); document.write( "Since the base b is positive (\"b%3E0\"), the base \"b\" raised to the power of y must be positive (\"b%5Ey%3E0\") for any real \"y\". So the number \"x\" must be positive (\"x%3E0\").\r
\n" ); document.write( "\n" ); document.write( "The real base \"b\" logarithm of a \"negative\" number is \"undefined\".\r
\n" ); document.write( "\n" ); document.write( "\"log%28b%2Cx%29\" is undefined for \"x+%3C=+0\"\r
\n" ); document.write( "\n" ); document.write( "For example, the base \"log%2810%2C+-5%29\" is \"undefined\".\r
\n" ); document.write( "\n" ); document.write( "so, if \"x=-12\", logarithm is \"undefined\"\r
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